What is the inverse of f(x)=-sqrt(x-2),2<= x<= 6 ?

The inverse of f(x)=-sqrt(x-2),2<= x<= 6 is x^2+2

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inverse of f(x)=-sqrt(x-2),2<= x<= 6

inverse

f (x) = - x - 2, 2 \leq x \leq 6

x^{2} + 2

Solution steps

y = - x - 2

Replace

x

with

y

x = - y - 2

Solve for

y, x = - y - 2

x^{2} + 2

(y - 1)^{2}

f (x) = ln (6 - 2 x)

f (x) = x^{2} - 8 b x

f (x) = 2 x - 14

f (x) = \frac{5}{3 x + 7}

What is the inverse of f(x)=-sqrt(x-2),2<= x<= 6 ?
The inverse of f(x)=-sqrt(x-2),2<= x<= 6 is x^2+2