What is the inverse of tan(x)((sqrt(3))/2)/((-1)/2) ?

The inverse of tan(x)((sqrt(3))/2)/((-1)/2) is arctan(-(sqrt(3)x)/3)

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inverse of tan(x)((sqrt(3))/2)/((-1)/2)

inverse

tan (x) \frac{\frac{3}{2}}{\frac{- 1}{2}}

arctan (- \frac{3 x}{3})

Solution steps

Solve for

tan (x), y = tan (x) \frac{\frac{3}{2}}{\frac{- 1}{2}}

tan (x) = - \frac{3 y}{3}

tan (a) = b \Rightarrow a = arctan (b)

arctan (- \frac{3 y}{3})

Substitute

y = x

arctan (- \frac{3 x}{3})

f (x) = \frac{- 5 + 3 x}{2}

f (x) = \frac{1}{x ^{2}} + 2

f (x) = \frac{2}{π} \cdot sin (r)

\frac{2}{x + 1} - 5

\frac{1}{x - 3} + \frac{1}{2}

What is the inverse of tan(x)((sqrt(3))/2)/((-1)/2) ?
The inverse of tan(x)((sqrt(3))/2)/((-1)/2) is arctan(-(sqrt(3)x)/3)