What is the inverse of g(x)=x^2+2x+1 ?

The inverse of g(x)=x^2+2x+1 is -1+sqrt(x),-sqrt(x)-1

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inverse of g(x)=x^2+2x+1

inverse

g (x) = x^{2} + 2 x + 1

- 1 + x, - x - 1

Solution steps

y = x^{2} + 2 x + 1

Replace

x

with

y

x = y^{2} + 2 y + 1

Solve for

y, x = y^{2} + 2 y + 1

- 1 + x, - x - 1

f (x) = y^{2} - 5

f (x) = \frac{5}{3 x + 8}

f (x) = (x + 5)^{2} - 1

f (x) = - lo g_{5} (- \frac{1}{3} x - 1) + 6

f (x) = \frac{x}{2 x - 7}

What is the inverse of g(x)=x^2+2x+1 ?
The inverse of g(x)=x^2+2x+1 is -1+sqrt(x),-sqrt(x)-1