What is the inverse of f(x)=-4x^2-9 ?

The inverse of f(x)=-4x^2-9 is sqrt(-(x+9)/4),-sqrt(-(x+9)/4)

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inverse of f(x)=-4x^2-9

inverse

f (x) = - 4 x^{2} - 9

- \frac{x + 9}{4}, - - \frac{x + 9}{4}

Solution steps

y = - 4 x^{2} - 9

Replace

x

with

y

x = - 4 y^{2} - 9

Solve for

y, x = - 4 y^{2} - 9

- \frac{x + 9}{4}, - - \frac{x + 9}{4}

f (x) = \frac{2 x + 5}{x ^{2} + 6 x + 34}

y = g^{- 1} (7)

y = \frac{x - 8}{5}

k (x) = \frac{5 - 2 x}{2 - x}

y = 1500 e^{- 0.05 x}

What is the inverse of f(x)=-4x^2-9 ?
The inverse of f(x)=-4x^2-9 is sqrt(-(x+9)/4),-sqrt(-(x+9)/4)