What is the inverse of 0.2log_{7}(3x+2)-9 ?

The inverse of 0.2log_{7}(3x+2)-9 is (16807^{x+9}-2)/3

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inverse of 0.2log_{7}(3x+2)-9

inverse

0.2 lo g_{7} (3 x + 2) - 9

\frac{1680 7 ^{x + 9} - 2}{3}

Solution steps

y = 0.2 lo g_{7} (3 x + 2) - 9

Replace

x

with

y

x = 0.2 lo g_{7} (3 y + 2) - 9

Solve for

y, x = 0.2 lo g_{7} (3 y + 2) - 9

\frac{1680 7 ^{x + 9} - 2}{3}

f (x) = \frac{1}{2 x ^{2} + 1}

f (x) = 160 e^{- 0.0165 x}

9 x^{2} - 4

f (x) = \frac{x - 8}{11}

h (x) = - x^{2} + 6, x \geq 0

What is the inverse of 0.2log_{7}(3x+2)-9 ?
The inverse of 0.2log_{7}(3x+2)-9 is (16807^{x+9}-2)/3