What is the inverse of 2pix^2+8pix ?

The inverse of 2pix^2+8pix is (-8pi+sqrt(64pi^2+8pix))/(4pi),(-8pi-sqrt(64pi^2+8pix))/(4pi)

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inverse of 2pix^2+8pix

inverse

2 π x^{2} + 8 π x

\frac{- 8 π + 64 π ^{2} + 8 π x}{4 π}, \frac{- 8 π - 64 π ^{2} + 8 π x}{4 π}

Solution steps

y = 2 π x^{2} + 8 π x

Replace

x

with

y

x = 2 π y^{2} + 8 π y

Solve for

y, x = 2 π y^{2} + 8 π y

\frac{- 8 π + 64 π ^{2} + 8 π x}{4 π}, \frac{- 8 π - 64 π ^{2} + 8 π x}{4 π}

arcsin (\frac{x - 1}{2})

f (x) = 9 x + 7

f (x) = 10 x^{(- \frac{1}{2})}

2 - lo g_{2} (4 - 2 x)

h (x) = 2 x - 13

What is the inverse of 2pix^2+8pix ?
The inverse of 2pix^2+8pix is (-8pi+sqrt(64pi^2+8pix))/(4pi),(-8pi-sqrt(64pi^2+8pix))/(4pi)