What is the inverse of 1/(6x^2+9x-2) ?

The inverse of 1/(6x^2+9x-2) is (-9x+sqrt(129x^2+24x))/(12x),(-9x-sqrt(129x^2+24x))/(12x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of 1/(6x^2+9x-2)

inverse

\frac{1}{6 x ^{2} + 9 x - 2}

\frac{- 9 x + 129 x ^{2} + 24 x}{12 x}, \frac{- 9 x - 129 x ^{2} + 24 x}{12 x}

Solution steps

y = \frac{1}{6 x ^{2} + 9 x - 2}

Replace

x

with

y

x = \frac{1}{6 y ^{2} + 9 y - 2}

Solve for

y, x = \frac{1}{6 y ^{2} + 9 y - 2}

\frac{- 9 x + 129 x ^{2} + 24 x}{12 x}, \frac{- 9 x - 129 x ^{2} + 24 x}{12 x}

f (x) = (\frac{x ^{\frac{1}{3}} + 5}{10})^{7}

f (x) = \frac{x - 3}{- 2 x - 4}

f (x) = 7 x^{2} + 4, x \geq 0

f (x) = - 15 x^{2} + 350 x - 200

f (x) = x - 4 - 2

What is the inverse of 1/(6x^2+9x-2) ?
The inverse of 1/(6x^2+9x-2) is (-9x+sqrt(129x^2+24x))/(12x),(-9x-sqrt(129x^2+24x))/(12x)