What is the inverse of-3(y+2)^2+1 ?

The inverse of-3(y+2)^2+1 is sqrt(-(y-1)/3)-2,-sqrt(-(y-1)/3)-2

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inverse of-3(y+2)^2+1

inverse

- 3 (y + 2)^{2} + 1

- \frac{y - 1}{3} - 2, - - \frac{y - 1}{3} - 2

Solution steps

y = - 3 (y + 2)^{2} + 1

Replace

y

with

y

y = - 3 (y + 2)^{2} + 1

Solve for

y, y = - 3 (y + 2)^{2} + 1

- \frac{y - 1}{3} - 2, - - \frac{y - 1}{3} - 2

f (x) = 2 π r^{2} + 2 π r

f (x) = - \frac{2 x}{3} - 6

f (x) = \frac{5 x - 2}{3 + 8 x}

2 3 x - 3

f (x) = 16 - 2 x

What is the inverse of-3(y+2)^2+1 ?
The inverse of-3(y+2)^2+1 is sqrt(-(y-1)/3)-2,-sqrt(-(y-1)/3)-2