What is the inverse of f(x)=(4x^2)/(x^2+10) ?

The inverse of f(x)=(4x^2)/(x^2+10) is sqrt(-(10x)/(x-4)),-sqrt(-(10x)/(x-4))

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inverse of f(x)=(4x^2)/(x^2+10)

inverse

f (x) = \frac{4 x ^{2}}{x ^{2} + 10}

- \frac{10 x}{x - 4}, - - \frac{10 x}{x - 4}

Solution steps

y = \frac{4 x ^{2}}{x ^{2} + 10}

Replace

x

with

y

x = \frac{4 y ^{2}}{y ^{2} + 10}

Solve for

y, x = \frac{4 y ^{2}}{y ^{2} + 10}

- \frac{10 x}{x - 4}, - - \frac{10 x}{x - 4}

f (x) = \frac{e ^{x} - 7}{e ^{x} + 2}

\frac{7 x + 5}{x + 9} + \frac{8 x - 10}{x + 9}

f (x) = e^{x} + 5

f (x) = 12 + 5 x - 5

f (x) = \frac{x}{3 x + 5}

What is the inverse of f(x)=(4x^2)/(x^2+10) ?
The inverse of f(x)=(4x^2)/(x^2+10) is sqrt(-(10x)/(x-4)),-sqrt(-(10x)/(x-4))