What is the inverse of f(x)=\sqrt[3]{x-3}+4 ?

The inverse of f(x)=\sqrt[3]{x-3}+4 is x^3-12x^2+48x-61

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inverse of f(x)=\sqrt[3]{x-3}+4

inverse

x^{3} - 12 x^{2} + 48 x - 61

Solution steps

Replace

x

with

y

Solve for

x^{3} - 12 x^{2} + 48 x - 61

f (x) = (1.4)

x^{2} + 8 x + 18

f (x) = \frac{5 x - 7}{7 x + 9}

f (x) = x^{\frac{1}{2}} + 4

What is the inverse of f(x)=\sqrt[3]{x-3}+4 ?
The inverse of f(x)=\sqrt[3]{x-3}+4 is x^3-12x^2+48x-61