What is the inverse of f(x)=((4x-3x))/((4x-2)) ?

The inverse of f(x)=((4x-3x))/((4x-2)) is (2x)/(4x-1)

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inverse of f(x)=((4x-3x))/((4x-2))

inverse

f (x) = \frac{( 4 x - 3 x )}{( 4 x - 2 )}

\frac{2 x}{4 x - 1}

Solution steps

y = \frac{4 x - 3 x}{4 x - 2}

Replace

x

with

y

x = \frac{4 y - 3 y}{4 y - 2}

Solve for

y, x = \frac{4 y - 3 y}{4 y - 2}

\frac{2 x}{4 x - 1}

x^{4} - 2 x^{2} + 3

f (x) = 2 x + 5

f (x) = \frac{1}{2} lo g_{10} (4 x)

\frac{x - 2}{3}

What is the inverse of f(x)=((4x-3x))/((4x-2)) ?
The inverse of f(x)=((4x-3x))/((4x-2)) is (2x)/(4x-1)