What is the inverse of f(x)=9x^2-18x+5 ?

The inverse of f(x)=9x^2-18x+5 is (3+sqrt(x+4))/3 ,(3-sqrt(x+4))/3

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inverse of f(x)=9x^2-18x+5

inverse

f (x) = 9 x^{2} - 18 x + 5

\frac{3 + x + 4}{3}, \frac{3 - x + 4}{3}

Solution steps

y = 9 x^{2} - 18 x + 5

Replace

x

with

y

x = 9 y^{2} - 18 y + 5

Solve for

y, x = 9 y^{2} - 18 y + 5

\frac{3 + x + 4}{3}, \frac{3 - x + 4}{3}

f (x) = + 4 - x

f (x) = \frac{( x ^{2} + 5 x ) 1}{2}

\frac{1}{2} x^{1 - \frac{1}{2}}

f (x) = \frac{x + 5}{3 x - 2}

What is the inverse of f(x)=9x^2-18x+5 ?
The inverse of f(x)=9x^2-18x+5 is (3+sqrt(x+4))/3 ,(3-sqrt(x+4))/3