What is the inverse of (x^2+2x-3)/(x+1) ?

The inverse of (x^2+2x-3)/(x+1) is (-2+x+sqrt(x^2+16))/2 ,(-2+x-sqrt(x^2+16))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of (x^2+2x-3)/(x+1)

inverse

\frac{x ^{2} + 2 x - 3}{x + 1}

\frac{- 2 + x + x ^{2} + 16}{2}, \frac{- 2 + x - x ^{2} + 16}{2}

Solution steps

y = \frac{x ^{2} + 2 x - 3}{x + 1}

Replace

x

with

y

x = \frac{y ^{2} + 2 y - 3}{y + 1}

Solve for

y, x = \frac{y ^{2} + 2 y - 3}{y + 1}

\frac{- 2 + x + x ^{2} + 16}{2}, \frac{- 2 + x - x ^{2} + 16}{2}

y = 1 - lo g_{2} (x - 1)

f (7) = - 5 x + 2

- \frac{7}{1 + x ^{2}}

f (x) = 11 x^{2} - 4

f (x) = 11 x^{2} - 1

What is the inverse of (x^2+2x-3)/(x+1) ?
The inverse of (x^2+2x-3)/(x+1) is (-2+x+sqrt(x^2+16))/2 ,(-2+x-sqrt(x^2+16))/2