What is the inverse of y=1-1/(2^{x/c)} ?

The inverse of y=1-1/(2^{x/c)} is -(cln(1-x))/(ln(2))

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inverse of y=1-1/(2^{x/c)}

inverse

y = 1 - \frac{1}{2 ^{\frac{x}{c}}}

- \frac{c ln ( 1 - x )}{ln ( 2 )}

Solution steps

y = 1 - \frac{1}{2 ^{\frac{x}{c}}}

Replace

x

with

y

x = 1 - \frac{1}{2 ^{\frac{y}{c}}}

Solve for

y, x = 1 - \frac{1}{2 ^{\frac{y}{c}}}

- \frac{c ln ( 1 - x )}{ln ( 2 )}

f (x) = \frac{3}{- x + 1}

f (x) = (\frac{1}{2})^{x} + 1, x < 0

f (x) = \frac{( 2 ^{x} - 1 )}{( 2 ^{x} + 1 )}

\frac{1}{( 1 - x ) ^{2}}

- \frac{1}{x} + 2

What is the inverse of y=1-1/(2^{x/c)} ?
The inverse of y=1-1/(2^{x/c)} is -(cln(1-x))/(ln(2))