What is the inverse of f(t)=2(x-3)^2+4 ?

The inverse of f(t)=2(x-3)^2+4 is sqrt((x-4)/2)+3,-sqrt((x-4)/2)+3

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inverse of f(t)=2(x-3)^2+4

inverse

f (t) = 2 (x - 3)^{2} + 4

\frac{x - 4}{2} + 3, - \frac{x - 4}{2} + 3

Solution steps

t = 2 (x - 3)^{2} + 4

Replace

x

with

t

x = 2 (t - 3)^{2} + 4

Solve for

t, x = 2 (t - 3)^{2} + 4

\frac{x - 4}{2} + 3, - \frac{x - 4}{2} + 3

f (x) = 3 + x + 4

\frac{7}{x} - 9

\frac{7}{x} - 4

f (x) = (x + 5) (x - 2)

f (x) = 5 - x, 0 < x \leq 6

What is the inverse of f(t)=2(x-3)^2+4 ?
The inverse of f(t)=2(x-3)^2+4 is sqrt((x-4)/2)+3,-sqrt((x-4)/2)+3