What is the domain of (x-3)/(x^2-4x-12) ?

The domain of (x-3)/(x^2-4x-12) is x 6

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domain of (x-3)/(x^2-4x-12)

domain

\frac{x - 3}{x ^{2} - 4 x - 12}

x < - 2 or - 2 < x < 6 or x > 6

Interval Notation

(- \infty, - 2) \cup (- 2, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

x = 6, x = - 2

The function domain

x < - 2 or - 2 < x < 6 or x > 6

3 x - 2 y - 5 = 0

f (x) = 1 - x^{2} f (x) = x

f (x) = \frac{1 + x}{x ^{3} - 9 x}

f (x) = 0.125 x^{3}

y = 3 x + 6, (1, 1)

What is the domain of (x-3)/(x^2-4x-12) ?
The domain of (x-3)/(x^2-4x-12) is x<-2\lor-2<x<6\lor x>6