What is the inverse of f(x)=sqrt(-2x^2+2*x+4) ?

The inverse of f(x)=sqrt(-2x^2+2*x+4) is -(-1+sqrt(-2x^2+9))/2 ,(sqrt(-2x^2+9)+1)/2

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inverse of f(x)=sqrt(-2x^2+2*x+4)

inverse

f (x) = - 2 x^{2} + 2 \cdot x + 4

- \frac{- 1 + - 2 x ^{2} + 9}{2}, \frac{- 2 x ^{2} + 9 + 1}{2}

Solution steps

y = - 2 x^{2} + 2 x + 4

Replace

x

with

y

x = - 2 y^{2} + 2 y + 4

Solve for

y, x = - 2 y^{2} + 2 \cdot y + 4

- \frac{- 1 + - 2 x ^{2} + 9}{2}, \frac{- 2 x ^{2} + 9 + 1}{2}

100 \cdot 2^{\frac{x}{2}}

\frac{5 x + 2}{3}

\frac{x - 3}{- x + 2}

- 10.5

f (x) = \frac{9 z - 3}{9 z + 7}

What is the inverse of f(x)=sqrt(-2x^2+2*x+4) ?
The inverse of f(x)=sqrt(-2x^2+2*x+4) is -(-1+sqrt(-2x^2+9))/2 ,(sqrt(-2x^2+9)+1)/2