What is the inverse of g(x)=(100)/(x-12)+8 ?

The inverse of g(x)=(100)/(x-12)+8 is (-12x-4)/(-x+8)

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inverse of g(x)=(100)/(x-12)+8

inverse

g (x) = \frac{100}{x - 12} + 8

\frac{- 12 x - 4}{- x + 8}

Solution steps

y = \frac{100}{x - 12} + 8

Replace

x

with

y

x = \frac{100}{y - 12} + 8

Solve for

y, x = \frac{100}{y - 12} + 8

\frac{- 12 x - 4}{- x + 8}

2 - 3 cos (2 x)

\frac{4 x + 3}{2 - x}

f (x) = - x - 7

y = ln (x - 1) - ln (2 x + 1)

\frac{1}{( x ^{2} - 2 x + 2 ) ^{2}}

What is the inverse of g(x)=(100)/(x-12)+8 ?
The inverse of g(x)=(100)/(x-12)+8 is (-12x-4)/(-x+8)