What is the inverse of f(x)=log_{2}(x+1)+3 ?

The inverse of f(x)=log_{2}(x+1)+3 is 2^{x-3}-1

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inverse of f(x)=log_{2}(x+1)+3

inverse

f (x) = lo g_{2} (x + 1) + 3

2^{x - 3} - 1

Solution steps

y = lo g_{2} (x + 1) + 3

Replace

x

with

y

x = lo g_{2} (y + 1) + 3

Solve for

y, x = lo g_{2} (y + 1) + 3

2^{x - 3} - 1

g (x) = \frac{x + 5}{3}

f (x) = - x - 2

- \frac{6}{7} x + \frac{32}{7}

lo g_{10} (0.001)

f (x) = 5 t + 4

What is the inverse of f(x)=log_{2}(x+1)+3 ?
The inverse of f(x)=log_{2}(x+1)+3 is 2^{x-3}-1