What is the inverse of 2(x-1)^2-4 ?

The inverse of 2(x-1)^2-4 is sqrt((x+4)/2)+1,-sqrt((x+4)/2)+1

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inverse of 2(x-1)^2-4

inverse

2 (x - 1)^{2} - 4

\frac{x + 4}{2} + 1, - \frac{x + 4}{2} + 1

Solution steps

y = 2 (x - 1)^{2} - 4

Replace

x

with

y

x = 2 (y - 1)^{2} - 4

Solve for

y, x = 2 (y - 1)^{2} - 4

\frac{x + 4}{2} + 1, - \frac{x + 4}{2} + 1

f (x) = \frac{x + 5}{2 - 7 x}

y = lo g_{10} (a) \frac{1}{x}

f (x) = ln (4 + ln (x))

2^{5 x + 1} - 1

f (z) = \frac{z ^{2} - z}{z + 1}

What is the inverse of 2(x-1)^2-4 ?
The inverse of 2(x-1)^2-4 is sqrt((x+4)/2)+1,-sqrt((x+4)/2)+1