What is the inverse of f(x)=log_{2}(x+1)-2 ?

The inverse of f(x)=log_{2}(x+1)-2 is 2^{x+2}-1

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inverse of f(x)=log_{2}(x+1)-2

inverse

f (x) = lo g_{2} (x + 1) - 2

2^{x + 2} - 1

Solution steps

y = lo g_{2} (x + 1) - 2

Replace

x

with

y

x = lo g_{2} (y + 1) - 2

Solve for

y, x = lo g_{2} (y + 1) - 2

2^{x + 2} - 1

f (x) = 4 (1 - x^{2})

y = 3 \cdot (2^{4 x - 5})

f (x) = 2 0.5 x + 1 + 2

x + 10 - x

What is the inverse of f(x)=log_{2}(x+1)-2 ?
The inverse of f(x)=log_{2}(x+1)-2 is 2^{x+2}-1