What is the inverse of y=(2x^2+3)/(5-x^2) ?

The inverse of y=(2x^2+3)/(5-x^2) is sqrt(-(3-5x)/(2+x)),-sqrt(-(3-5x)/(2+x))

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inverse of y=(2x^2+3)/(5-x^2)

inverse

y = \frac{2 x ^{2} + 3}{5 - x ^{2}}

- \frac{3 - 5 x}{2 + x}, - - \frac{3 - 5 x}{2 + x}

Solution steps

y = \frac{2 x ^{2} + 3}{5 - x ^{2}}

Replace

x

with

y

x = \frac{2 y ^{2} + 3}{5 - y ^{2}}

Solve for

y, x = \frac{2 y ^{2} + 3}{5 - y ^{2}}

- \frac{3 - 5 x}{2 + x}, - - \frac{3 - 5 x}{2 + x}

f (x) = 4 + 23 x - 10

f (x) = e^{234 - 10} 34 - 1

f (x) = \frac{x - 4}{x + 7}

f (x) = 2 (x - 1)^{3} + \frac{1}{2}

y = \frac{x + 4}{x - 6}

What is the inverse of y=(2x^2+3)/(5-x^2) ?
The inverse of y=(2x^2+3)/(5-x^2) is sqrt(-(3-5x)/(2+x)),-sqrt(-(3-5x)/(2+x))