What is the inverse of y=-2(x-1)^2+5 ?

The inverse of y=-2(x-1)^2+5 is sqrt(-(x-5)/2)+1,-sqrt(-(x-5)/2)+1

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inverse of y=-2(x-1)^2+5

inverse

y = - 2 (x - 1)^{2} + 5

- \frac{x - 5}{2} + 1, - - \frac{x - 5}{2} + 1

Solution steps

y = - 2 (x - 1)^{2} + 5

Replace

x

with

y

x = - 2 (y - 1)^{2} + 5

Solve for

y, x = - 2 (y - 1)^{2} + 5

- \frac{x - 5}{2} + 1, - - \frac{x - 5}{2} + 1

f (x) = \frac{7 x + 9}{x - 2}

\frac{x + 4}{x + 12}

1.491 w

\frac{1 - x}{x - 3}

\frac{2}{( s ^{2} + 1 ) ( s ^{2} + 2 )}

What is the inverse of y=-2(x-1)^2+5 ?
The inverse of y=-2(x-1)^2+5 is sqrt(-(x-5)/2)+1,-sqrt(-(x-5)/2)+1