What is the inverse of P(t)=(100000)/(100+900e^{-t)} ?

The inverse of P(t)=(100000)/(100+900e^{-t)} is -ln((1000-t)/(9t))

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inverse of P(t)=(100000)/(100+900e^{-t)}

inverse

P (t) = \frac{100000}{100 + 900 e ^{- t}}

- ln (\frac{1000 - t}{9 t})

Solution steps

y = \frac{100000}{100 + 900 e ^{- t}}

Replace

t

with

y

t = \frac{100000}{100 + 900 e ^{- y}}

Solve for

y, t = \frac{100000}{100 + 900 e ^{- y}}

- ln (\frac{1000 - t}{9 t})

f (x) = \frac{3}{π} arccos (x)

y = \frac{5 x - 4}{2 x - 3}

3^{(x + 7)} + 2

f (x) = f (x) = - 8 - 5 x

+ \frac{z}{( z + 1 ) ^{2}}

What is the inverse of P(t)=(100000)/(100+900e^{-t)} ?
The inverse of P(t)=(100000)/(100+900e^{-t)} is -ln((1000-t)/(9t))