What is the inverse of d/d arctan(7x+10) ?

The inverse of d/d arctan(7x+10) is (tan(x)-10)/7

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inverse of d/d arctan(7x+10)

inverse

\frac{d}{d} arctan (7 x + 10)

\frac{tan ( x ) - 10}{7}

Solution steps

Solve for

arctan (7 x + 10), y = \frac{d}{d} arctan (7 x + 10)

arctan (7 x + 10) = y

arctan (a) = b \Rightarrow a = tan (b)

7 x + 10 = tan (y)

Solve for

x, 7 x + 10 = tan (y)

\frac{tan ( y ) - 10}{7}

Substitute

y = x

\frac{tan ( x ) - 10}{7}

f (x) = \frac{( 6 y + 2 )}{( 2 y + 3 )}

(2.5 e^{- 1.7 x} + 7), x = 0.3

g (x) = \frac{( 6 x )}{( x - 1 )}

\frac{2}{3} x - 4

f (x) = \frac{( 5 + 5 x - 3 )}{4}

What is the inverse of d/d arctan(7x+10) ?
The inverse of d/d arctan(7x+10) is (tan(x)-10)/7