What is the inverse of y= 1/40 ln(0.1x)+30 ?

The inverse of y= 1/40 ln(0.1x)+30 is e^{40x-1200}*10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of y= 1/40 ln(0.1x)+30

inverse

y = \frac{1}{40} ln (0.1 x) + 30

e^{40 x - 1200} \cdot 10

Solution steps

y = \frac{1}{40} ln (0.1 x) + 30

Replace

x

with

y

x = \frac{1}{40} ln (0.1 y) + 30

Solve for

y, x = \frac{1}{40} ln (0.1 y) + 30

e^{40 x - 1200} \cdot 10

- 4 x^{2} - 6 x + 3

f (x) = - e^{- x} + 8

f (x) = - e^{- x} + 5

y = \frac{- x - 13}{7}

\frac{d}{d} \frac{1}{3 x + 4}

What is the inverse of y= 1/40 ln(0.1x)+30 ?
The inverse of y= 1/40 ln(0.1x)+30 is e^{40x-1200}*10