What is the inverse of f(n)=\sqrt[3]{n}-3 ?

The inverse of f(n)=\sqrt[3]{n}-3 is n^3+9n^2+27n+27

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inverse of f(n)=\sqrt[3]{n}-3

inverse

n^{3} + 9 n^{2} + 27 n + 27

Solution steps

Replace

n

with

y

Solve for

n^{3} + 9 n^{2} + 27 n + 27

f (x) = 1 0^{x - 2} + 4

f (x) = 8 (x - 7)^{2} + 22

y = \frac{3}{2} x + 4

f (x) = \frac{x}{x - 25}

f (x) = 5 \cdot 7^{1 - x}

What is the inverse of f(n)=\sqrt[3]{n}-3 ?
The inverse of f(n)=\sqrt[3]{n}-3 is n^3+9n^2+27n+27