What is the inverse of f(x)=x^2-8x+18 ?

The inverse of f(x)=x^2-8x+18 is 4+sqrt(x-2),4-sqrt(x-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=x^2-8x+18

inverse

f (x) = x^{2} - 8 x + 18

4 + x - 2, 4 - x - 2

Solution steps

y = x^{2} - 8 x + 18

Replace

x

with

y

x = y^{2} - 8 y + 18

Solve for

y, x = y^{2} - 8 y + 18

4 + x - 2, 4 - x - 2

6 x + 7

\frac{1}{10 - 5}

\frac{d}{d} 3 x

\frac{3 x + 1}{11 x - 2}

y = \frac{1 - 10 \frac{7 - x}{2}}{4}

What is the inverse of f(x)=x^2-8x+18 ?
The inverse of f(x)=x^2-8x+18 is 4+sqrt(x-2),4-sqrt(x-2)