What is the inverse of f(x)=x^2,1<= x<= 4 ?

The inverse of f(x)=x^2,1<= x<= 4 is sqrt(x),-sqrt(x)

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inverse of f(x)=x^2,1<= x<= 4

inverse

f (x) = x^{2}, 1 \leq x \leq 4

x, - x

Solution steps

y = x^{2}

Replace

x

with

y

x = y^{2}

Solve for

y, x = y^{2}

x, - x

f (x) = \frac{( 4 x + 5 )}{( x + 4 )}

f (x) = 8 (x - 3) + 27

6 x - 6

y = x^{2} - 2 x + 2

tan (5)

What is the inverse of f(x)=x^2,1<= x<= 4 ?
The inverse of f(x)=x^2,1<= x<= 4 is sqrt(x),-sqrt(x)