What is the inverse of f(x)=(x-10)^2,x<= 10 ?

The inverse of f(x)=(x-10)^2,x<= 10 is sqrt(x)+10,-sqrt(x)+10

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inverse of f(x)=(x-10)^2,x<= 10

inverse

f (x) = (x - 10)^{2}, x \leq 10

x + 10, - x + 10

Solution steps

y = (x - 10)^{2}

Replace

x

with

y

x = (y - 10)^{2}

Solve for

y, x = (y - 10)^{2}

x + 10, - x + 10

f (x) = \frac{x}{x - 18}

\frac{2 - ( 1 - 3 x )}{2 x - 5}

f (x) = \frac{1}{1000 x + 1}

f (x) = \frac{7 x}{5 - 3 x}

f (x) = cos (5 x)

What is the inverse of f(x)=(x-10)^2,x<= 10 ?
The inverse of f(x)=(x-10)^2,x<= 10 is sqrt(x)+10,-sqrt(x)+10