What is the inverse of-(1/12)^{(x+2)}+1 ?

The inverse of-(1/12)^{(x+2)}+1 is -(ln(1-x))/(ln(12))-2

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inverse of-(1/12)^{(x+2)}+1

inverse

- (\frac{1}{12})^{(x + 2)} + 1

- \frac{ln ( 1 - x )}{ln ( 12 )} - 2

Solution steps

y = - (\frac{1}{12})^{x + 2} + 1

Replace

x

with

y

x = - (\frac{1}{12})^{y + 2} + 1

Solve for

y, x = - (\frac{1}{12})^{y + 2} + 1

- \frac{ln ( 1 - x )}{ln ( 12 )} - 2

- 6 + x - 9

f (x) = \frac{- x}{x ^{2} + 1}

f (x) = \frac{x - 5}{6 x + 5}

3^{0.5 x}

2 x + 5 + 4

What is the inverse of-(1/12)^{(x+2)}+1 ?
The inverse of-(1/12)^{(x+2)}+1 is -(ln(1-x))/(ln(12))-2