What is the inverse of log_{5}(sqrt(x-2))+1/2 ?

The inverse of log_{5}(sqrt(x-2))+1/2 is 5^{2x-1}+2

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inverse of log_{5}(sqrt(x-2))+1/2

inverse

lo g_{5} (x - 2) + \frac{1}{2}

5^{2 x - 1} + 2

Solution steps

y = lo g_{5} (x - 2) + \frac{1}{2}

Replace

x

with

y

x = lo g_{5} (y - 2) + \frac{1}{2}

Solve for

y, x = lo g_{5} (y - 2) + \frac{1}{2}

5^{2 x - 1} + 2

X - 4

f (x) = \frac{( 8 x - 1 )}{4}

f (x) = sin (x + \frac{π}{3})

f (x) = \frac{- 4 x + 3}{2}

f (x) = 590 (1.732)^{x}

What is the inverse of log_{5}(sqrt(x-2))+1/2 ?
The inverse of log_{5}(sqrt(x-2))+1/2 is 5^{2x-1}+2