What is the inverse of f(x)=x^2-3x+6 ?

The inverse of f(x)=x^2-3x+6 is (3+sqrt(4x-15))/2 ,(3-sqrt(4x-15))/2

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inverse of f(x)=x^2-3x+6

inverse

f (x) = x^{2} - 3 x + 6

\frac{3 + 4 x - 15}{2}, \frac{3 - 4 x - 15}{2}

Solution steps

y = x^{2} - 3 x + 6

Replace

x

with

y

x = y^{2} - 3 y + 6

Solve for

y, x = y^{2} - 3 y + 6

\frac{3 + 4 x - 15}{2}, \frac{3 - 4 x - 15}{2}

f (- 8) = \frac{X + 1}{X + 10}

f (x) = \frac{( x + 4 )}{( x + 6 )}

\frac{x + 9}{2}

lo g_{4} (x) + 3

f (x) = \frac{- ( x + 17 )}{4}

What is the inverse of f(x)=x^2-3x+6 ?
The inverse of f(x)=x^2-3x+6 is (3+sqrt(4x-15))/2 ,(3-sqrt(4x-15))/2