What is the inverse of f(x)=((3x+7))/(7x-9) ?

The inverse of f(x)=((3x+7))/(7x-9) is (7+9x)/(7x-3)

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inverse of f(x)=((3x+7))/(7x-9)

inverse

f (x) = \frac{( 3 x + 7 )}{7 x - 9}

\frac{7 + 9 x}{7 x - 3}

Solution steps

y = \frac{3 x + 7}{7 x - 9}

Replace

x

with

y

x = \frac{3 y + 7}{7 y - 9}

Solve for

y, x = \frac{3 y + 7}{7 y - 9}

\frac{7 + 9 x}{7 x - 3}

f (x) = - 9 x^{- 4}

f (x) = 5 + 6 + 7 x

f (x) = \frac{( x - 3 )}{5}

f (x) = \frac{- 7 x - 45}{x + 3}

f (x) = \frac{13 x}{50}

What is the inverse of f(x)=((3x+7))/(7x-9) ?
The inverse of f(x)=((3x+7))/(7x-9) is (7+9x)/(7x-3)