What is the inverse of f(x)=8+sqrt(4x-4) ?

The inverse of f(x)=8+sqrt(4x-4) is (x^2-16x+68)/4

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inverse of f(x)=8+sqrt(4x-4)

inverse

f (x) = 8 + 4 x - 4

\frac{x ^{2} - 16 x + 68}{4}

Solution steps

y = 8 + 4 x - 4

Replace

x

with

y

x = 8 + 4 y - 4

Solve for

y, x = 8 + 4 y - 4

\frac{x ^{2} - 16 x + 68}{4}

y = x^{2} - 6 x + 11

\frac{x}{8 x - 9}

f (x) = (\frac{1}{2} x)^{2}

f (x) = ((\frac{2}{3}) x) + 2

f (x) = \frac{( 1 )}{( x - 1 )}

What is the inverse of f(x)=8+sqrt(4x-4) ?
The inverse of f(x)=8+sqrt(4x-4) is (x^2-16x+68)/4