What is the inverse of f(x)=e(3*tan(3*x^3)) ?

The inverse of f(x)=e(3*tan(3*x^3)) is cube root of (arctan(x/(e3)))/3

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inverse of f(x)=e(3tan(3x^3))

inverse

f (x) = e (3 \cdot tan (3 \cdot x^{3}))

3 \frac{arctan ( \frac{x}{e 3} )}{3}

Solution steps

Solve for

tan (3 \cdot x^{3}), y = e 3 \cdot tan (3 \cdot x^{3})

tan (3 \cdot x^{3}) = \frac{y}{e 3}

tan (a) = b \Rightarrow a = arctan (b)

3 x^{3} = arctan (\frac{y}{e 3})

Solve for

x, 3 \cdot x^{3} = arctan (\frac{y}{e 3})

3 \frac{arctan ( \frac{y}{e 3} )}{3}

Substitute

y = x

3 \frac{arctan ( \frac{x}{e 3} )}{3}

[\frac{1}{2} 3 - 12]

f (x) = tan^{3} (x)

f (x) = cos (4 x)

y = \frac{x + 3}{x + 2}

1 - 2^{2}

What is the inverse of f(x)=e(3*tan(3*x^3)) ?
The inverse of f(x)=e(3*tan(3*x^3)) is cube root of (arctan(x/(e3)))/3