What is the inverse of (x-1/4)^2+2 ?

The inverse of (x-1/4)^2+2 is sqrt(x-2)+1/4 ,-sqrt(x-2)+1/4

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inverse of (x-1/4)^2+2

inverse

(x - \frac{1}{4})^{2} + 2

x - 2 + \frac{1}{4}, - x - 2 + \frac{1}{4}

Solution steps

y = (x - \frac{1}{4})^{2} + 2

Replace

x

with

y

x = (y - \frac{1}{4})^{2} + 2

Solve for

y, x = (y - \frac{1}{4})^{2} + 2

x - 2 + \frac{1}{4}, - x - 2 + \frac{1}{4}

\frac{9 x - 4}{- 3 x + 1}

f (x) = 3 x^{2} - 3

\frac{\frac{4}{x} - 12}{x - \frac{1}{9}}

f (x) = 3 x^{2} - 1

y = \frac{x - 1}{x}

What is the inverse of (x-1/4)^2+2 ?
The inverse of (x-1/4)^2+2 is sqrt(x-2)+1/4 ,-sqrt(x-2)+1/4