What is the inverse of f(x)=x^2-3,x>= 0 ?

The inverse of f(x)=x^2-3,x>= 0 is sqrt(x+3),-sqrt(x+3)

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inverse of f(x)=x^2-3,x>= 0

inverse

f (x) = x^{2} - 3, x \geq 0

x + 3, - x + 3

Solution steps

y = x^{2} - 3

Replace

x

with

y

x = y^{2} - 3

Solve for

y, x = y^{2} - 3

x + 3, - x + 3

f (x) = (2 x + 3) = 5 x - 2

f (x) = 3 - lo g_{\frac{1}{5}} (1 + x)

f (x) = - x - 5 + 3

g (x) = x + 6

- 4 x^{3} - 7

What is the inverse of f(x)=x^2-3,x>= 0 ?
The inverse of f(x)=x^2-3,x>= 0 is sqrt(x+3),-sqrt(x+3)