What is the inverse of f(x)=x^2+bx ?

The inverse of f(x)=x^2+bx is (-b+sqrt(b^2+4x))/2 ,(-b-sqrt(b^2+4x))/2

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inverse of f(x)=x^2+bx

inverse

f (x) = x^{2} + b x

\frac{- b + b ^{2} + 4 x}{2}, \frac{- b - b ^{2} + 4 x}{2}

Solution steps

y = x^{2} + b x

Replace

x

with

y

x = y^{2} + b y

Solve for

y, x = y^{2} + b y

\frac{- b + b ^{2} + 4 x}{2}, \frac{- b - b ^{2} + 4 x}{2}

x^{2} - 20

x^{2} + 2, x \geq 0

f (x) = \frac{3}{2} (- x + 3)

ln (0.835)

y = 1 x + 1

What is the inverse of f(x)=x^2+bx ?
The inverse of f(x)=x^2+bx is (-b+sqrt(b^2+4x))/2 ,(-b-sqrt(b^2+4x))/2