What is the inverse of d/d-1/(x^2+1) ?

The inverse of d/d-1/(x^2+1) is sqrt(-x/(x-1)),-sqrt(-x/(x-1))

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inverse of d/d-1/(x^2+1)

inverse

\frac{d}{d} - \frac{1}{x ^{2} + 1}

- \frac{x}{x - 1}, - - \frac{x}{x - 1}

Solution steps

y = \frac{d}{d} - \frac{1}{x ^{2} + 1}

Replace

x

with

y

x = \frac{d}{d} - \frac{1}{y ^{2} + 1}

Solve for

y, x = \frac{d}{d} - \frac{1}{y ^{2} + 1}

- \frac{x}{x - 1}, - - \frac{x}{x - 1}

f (x) = \frac{x - 3}{2 x + 7}

y = \frac{x - 4}{33 - x}

sin (0.87)

- 4 + lo g_{2} (x + 1)

- 4 x + 13

What is the inverse of d/d-1/(x^2+1) ?
The inverse of d/d-1/(x^2+1) is sqrt(-x/(x-1)),-sqrt(-x/(x-1))