What is the inverse of f(x)=4x^2-16x+25 ?

The inverse of f(x)=4x^2-16x+25 is (4+sqrt(x-9))/2 ,(4-sqrt(x-9))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=4x^2-16x+25

inverse

f (x) = 4 x^{2} - 16 x + 25

\frac{4 + x - 9}{2}, \frac{4 - x - 9}{2}

Solution steps

y = 4 x^{2} - 16 x + 25

Replace

x

with

y

x = 4 y^{2} - 16 y + 25

Solve for

y, x = 4 y^{2} - 16 y + 25

\frac{4 + x - 9}{2}, \frac{4 - x - 9}{2}

\frac{( 7 x - 4 )}{2 x + 3}

\frac{- 5 - 4 x}{7 x - 2}

ln (arctan (7 x^{4}))

f (x) = y^{2} + 2

f (x) = (2 x + 3)

What is the inverse of f(x)=4x^2-16x+25 ?
The inverse of f(x)=4x^2-16x+25 is (4+sqrt(x-9))/2 ,(4-sqrt(x-9))/2