What is the inverse of f(x)=\sqrt[3]{4-x}+3 ?

The inverse of f(x)=\sqrt[3]{4-x}+3 is -x^3+9x^2-27x+31

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inverse of f(x)=\sqrt[3]{4-x}+3

inverse

f (x) = 3 4 - x + 3

- x^{3} + 9 x^{2} - 27 x + 31

Solution steps

y = 3 4 - x + 3

Replace

x

with

y

x = 3 4 - y + 3

Solve for

y, x = 3 4 - y + 3

- x^{3} + 9 x^{2} - 27 x + 31

f (x) = e^{\frac{( 5 - x ) \cdot l n ( 0.2 )}{5}}

f (x) = 15 x^{2} + 8

q (x) = 6 x - 4

0.975

ln (x - 1) + 1

What is the inverse of f(x)=\sqrt[3]{4-x}+3 ?
The inverse of f(x)=\sqrt[3]{4-x}+3 is -x^3+9x^2-27x+31