What is the inverse of+1200+500sin(0.3t) ?

The inverse of+1200+500sin(0.3t) is (arcsin((t-1200)/(500))*10)/3

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inverse of+1200+500sin(0.3t)

inverse

+ 1200 + 500 sin (0.3 t)

\frac{arcsin ( \frac{t - 1200}{500} ) \cdot 10}{3}

Solution steps

Solve for

sin (0.3 t), y = + 1200 + 500 sin (0.3 t)

sin (0.3 t) = \frac{y - 1200}{500}

sin (a) = b \Rightarrow a = arcsin (b)

0.3 t = arcsin (\frac{y - 1200}{500})

Solve for

t, 0.3 t = arcsin (\frac{y - 1200}{500})

\frac{arcsin ( \frac{y - 1200}{500} ) \cdot 10}{3}

Substitute

y = t

\frac{arcsin ( \frac{t - 1200}{500} ) \cdot 10}{3}

f (x) = \frac{4 - x}{3 x + 1}

f (x) = \frac{2 x - 8}{8 x + 4}

L - 19 s^{9} s^{2} + 1

f (x) = - 256 x^{3} - 6

f (x) = \frac{3 x}{2} - 3

What is the inverse of+1200+500sin(0.3t) ?
The inverse of+1200+500sin(0.3t) is (arcsin((t-1200)/(500))*10)/3