What is the inverse of f(x)=x^2-8x+10,x>= 4 ?

The inverse of f(x)=x^2-8x+10,x>= 4 is 4+sqrt(x+6),4-sqrt(x+6)

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inverse of f(x)=x^2-8x+10,x>= 4

inverse

f (x) = x^{2} - 8 x + 10, x \geq 4

4 + x + 6, 4 - x + 6

Solution steps

y = x^{2} - 8 x + 10

Replace

x

with

y

x = y^{2} - 8 y + 10

Solve for

y, x = y^{2} - 8 y + 10

4 + x + 6, 4 - x + 6

f (x) = x^{2} + 3 x - 21

2 (x - a) (x + 2 a)

f (x) = \frac{2}{x - 5} - 3

f (x) = 16, y = \frac{3}{8}

f (x) = - x^{2} + 11 x - 30

What is the inverse of f(x)=x^2-8x+10,x>= 4 ?
The inverse of f(x)=x^2-8x+10,x>= 4 is 4+sqrt(x+6),4-sqrt(x+6)