What is the inverse of f(x)=5x^2+3x ?

The inverse of f(x)=5x^2+3x is (-3+sqrt(9+20x))/(10),(-3-sqrt(9+20x))/(10)

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inverse of f(x)=5x^2+3x

inverse

f (x) = 5 x^{2} + 3 x

\frac{- 3 + 9 + 20 x}{10}, \frac{- 3 - 9 + 20 x}{10}

Solution steps

y = 5 x^{2} + 3 x

Replace

x

with

y

x = 5 y^{2} + 3 y

Solve for

y, x = 5 y^{2} + 3 y

\frac{- 3 + 9 + 20 x}{10}, \frac{- 3 - 9 + 20 x}{10}

cos (- 0.51698)

f (x) = 0.4346 x + 0.0238

y = 45 - 1.25 x

+ 3 cos (5 x - 9)

f (x) = \frac{6 - x}{5}

What is the inverse of f(x)=5x^2+3x ?
The inverse of f(x)=5x^2+3x is (-3+sqrt(9+20x))/(10),(-3-sqrt(9+20x))/(10)