What is the inverse of f(x)=((3x-7))/((7x+1)) ?

The inverse of f(x)=((3x-7))/((7x+1)) is (-7-x)/(7x-3)

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inverse of f(x)=((3x-7))/((7x+1))

inverse

f (x) = \frac{( 3 x - 7 )}{( 7 x + 1 )}

\frac{- 7 - x}{7 x - 3}

Solution steps

y = \frac{3 x - 7}{7 x + 1}

Replace

x

with

y

x = \frac{3 y - 7}{7 y + 1}

Solve for

y, x = \frac{3 y - 7}{7 y + 1}

\frac{- 7 - x}{7 x - 3}

f (x) = 3 (x + 1)^{3} - 1

f (x) = \frac{5 x + 6}{7 x + 7}

\frac{1 - e ^{x}}{e ^{x}}

f (x) = (\frac{( 2 x )}{( x ^{(2)} + 1 )})

\frac{x}{x ^{2} - x + 1}

What is the inverse of f(x)=((3x-7))/((7x+1)) ?
The inverse of f(x)=((3x-7))/((7x+1)) is (-7-x)/(7x-3)