What is the inverse of f(x)=((x-2))/((x-1)) ?

The inverse of f(x)=((x-2))/((x-1)) is (-2+x)/(x-1)

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inverse of f(x)=((x-2))/((x-1))

inverse

f (x) = \frac{( x - 2 )}{( x - 1 )}

\frac{- 2 + x}{x - 1}

Solution steps

y = \frac{x - 2}{x - 1}

Replace

x

with

y

x = \frac{y - 2}{y - 1}

Solve for

y, x = \frac{y - 2}{y - 1}

\frac{- 2 + x}{x - 1}

sin (3)

\frac{3 + 17 x}{8 - 2 x}

f (x) = cos (6 x)

1 + \frac{1}{2} (z^{- 1} + z)

- - \frac{x - 2}{3} + 1

What is the inverse of f(x)=((x-2))/((x-1)) ?
The inverse of f(x)=((x-2))/((x-1)) is (-2+x)/(x-1)