What is the inverse of f(x)=(-14x-19)^2 ?

The inverse of f(x)=(-14x-19)^2 is -(sqrt(x)+19)/(14),-(-sqrt(x)+19)/(14)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(-14x-19)^2

inverse

f (x) = (- 14 x - 19)^{2}

- \frac{x + 19}{14}, - \frac{- x + 19}{14}

Solution steps

y = (- 14 x - 19)^{2}

Replace

x

with

y

x = (- 14 y - 19)^{2}

Solve for

y, x = (- 14 y - 19)^{2}

- \frac{x + 19}{14}, - \frac{- x + 19}{14}

f (x) = 5 x^{2} + 3, x \geq 0

f (x) = b e^{- 2 b x}

e^{x - 1} - 4

\frac{- 3 x + 2}{9 x - 8}

lo g_{10} (\frac{3 b ^{2} + 21 b}{11 b + 77})

What is the inverse of f(x)=(-14x-19)^2 ?
The inverse of f(x)=(-14x-19)^2 is -(sqrt(x)+19)/(14),-(-sqrt(x)+19)/(14)