What is the inverse of f(x)=1-\sqrt[5]{x-5} ?

The inverse of f(x)=1-\sqrt[5]{x-5} is -x^5+5x^4-10x^3+10x^2-5x+6

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inverse of f(x)=1-\sqrt[5]{x-5}

inverse

f (x) = 1 - 5 x - 5

- x^{5} + 5 x^{4} - 10 x^{3} + 10 x^{2} - 5 x + 6

Solution steps

y = 1 - 5 x - 5

Replace

x

with

y

x = 1 - 5 y - 5

Solve for

y, x = 1 - 5 y - 5

- x^{5} + 5 x^{4} - 10 x^{3} + 10 x^{2} - 5 x + 6

\frac{3 x ^{2} - 13 x + 4}{2 x ^{2} + 7 x - 15}

f (x) = 9 cos (2 x) + 7, 0 \leq x \leq \frac{π}{2}

\frac{1}{5 x + 3}

f (x) = \frac{x - 1}{x - 1}

s^{6}

What is the inverse of f(x)=1-\sqrt[5]{x-5} ?
The inverse of f(x)=1-\sqrt[5]{x-5} is -x^5+5x^4-10x^3+10x^2-5x+6