What is the inverse of f(x)=sqrt(x^3)-2+1 ?

The inverse of f(x)=sqrt(x^3)-2+1 is cube root of x^2+2x+1

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inverse of f(x)=sqrt(x^3)-2+1

inverse

f (x) = x^{3} - 2 + 1

3 x^{2} + 2 x + 1

Solution steps

y = x^{3} - 2 + 1

Replace

x

with

y

x = y^{3} - 2 + 1

Solve for

y, x = y^{3} - 2 + 1

3 x^{2} + 2 x + 1

f (x) = \frac{6 x - 5}{x + 1}

\frac{y - 5}{y ^{2} - 3 y + 15}

y = 9 x^{2} - 5

y = 1.9 (x \cdot 0.00055)

\frac{( x + 2 )}{4}

What is the inverse of f(x)=sqrt(x^3)-2+1 ?
The inverse of f(x)=sqrt(x^3)-2+1 is cube root of x^2+2x+1